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-20x^2-20x+300=0
a = -20; b = -20; c = +300;
Δ = b2-4ac
Δ = -202-4·(-20)·300
Δ = 24400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24400}=\sqrt{400*61}=\sqrt{400}*\sqrt{61}=20\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{61}}{2*-20}=\frac{20-20\sqrt{61}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{61}}{2*-20}=\frac{20+20\sqrt{61}}{-40} $
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